Base | Representation |
---|---|
bin | 110000111011101110000010… |
… | …1000010001000100011011011 |
3 | 2002102222202212000122001022012 |
4 | 1201313130011002020203123 |
5 | 422404001113343422133 |
6 | 4123232154100420135 |
7 | 156442556411451335 |
oct | 14167340502104333 |
9 | 2072882760561265 |
10 | 430420232014043 |
11 | 115166216a37707 |
12 | 403363a89a764b |
13 | 156225b8a88b7b |
14 | 7840643bd6455 |
15 | 34b6340aebb48 |
hex | 18777050888db |
430420232014043 has 2 divisors, whose sum is σ = 430420232014044. Its totient is φ = 430420232014042.
The previous prime is 430420232014013. The next prime is 430420232014057. The reversal of 430420232014043 is 340410232024034.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 430420232014043 - 26 = 430420232013979 is a prime.
It is a super-2 number, since 2×4304202320140432 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (430420232014013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215210116007021 + 215210116007022.
It is an arithmetic number, because the mean of its divisors is an integer number (215210116007022).
Almost surely, 2430420232014043 is an apocalyptic number.
430420232014043 is a deficient number, since it is larger than the sum of its proper divisors (1).
430420232014043 is an equidigital number, since it uses as much as digits as its factorization.
430420232014043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 430420232014043 its reverse (340410232024034), we get a palindrome (770830464038077).
Subtracting from 430420232014043 its reverse (340410232024034), we obtain a palindrome (90009999990009).
The spelling of 430420232014043 in words is "four hundred thirty trillion, four hundred twenty billion, two hundred thirty-two million, fourteen thousand, forty-three".
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