Base | Representation |
---|---|
bin | 111110101000101100010… |
… | …001011100101011101111 |
3 | 120020111011001211110112202 |
4 | 332220230101130223233 |
5 | 1031010201300031111 |
6 | 13053211303052115 |
7 | 622655365230521 |
oct | 76505421345357 |
9 | 16214131743482 |
10 | 4304300002031 |
11 | 140a497158057 |
12 | 59625144103b |
13 | 252b80747733 |
14 | 10c4875a9a11 |
15 | 76e70dedb3b |
hex | 3ea2c45caef |
4304300002031 has 2 divisors, whose sum is σ = 4304300002032. Its totient is φ = 4304300002030.
The previous prime is 4304300002007. The next prime is 4304300002043. The reversal of 4304300002031 is 1302000034034.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4304300002031 is a prime.
It is a super-3 number, since 3×43043000020313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 4304300001994 and 4304300002012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4304300002001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2152150001015 + 2152150001016.
It is an arithmetic number, because the mean of its divisors is an integer number (2152150001016).
Almost surely, 24304300002031 is an apocalyptic number.
4304300002031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4304300002031 is an equidigital number, since it uses as much as digits as its factorization.
4304300002031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 20.
Adding to 4304300002031 its reverse (1302000034034), we get a palindrome (5606300036065).
The spelling of 4304300002031 in words is "four trillion, three hundred four billion, three hundred million, two thousand, thirty-one".
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