Base | Representation |
---|---|
bin | 111110101000101101100… |
… | …101110000000010101111 |
3 | 120020111012121102020012202 |
4 | 332220231211300002233 |
5 | 1031010222424221143 |
6 | 13053213412452115 |
7 | 622656054122321 |
oct | 76505545600257 |
9 | 16214177366182 |
10 | 4304322101423 |
11 | 140a4a8681713 |
12 | 59625891a03b |
13 | 252b851b45b6 |
14 | 10c48a4bd611 |
15 | 76e72d16ab8 |
hex | 3ea2d9700af |
4304322101423 has 2 divisors, whose sum is σ = 4304322101424. Its totient is φ = 4304322101422.
The previous prime is 4304322101411. The next prime is 4304322101437. The reversal of 4304322101423 is 3241012234034.
4304322101423 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4304322101423 - 226 = 4304254992559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4304322101483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2152161050711 + 2152161050712.
It is an arithmetic number, because the mean of its divisors is an integer number (2152161050712).
Almost surely, 24304322101423 is an apocalyptic number.
4304322101423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4304322101423 is an equidigital number, since it uses as much as digits as its factorization.
4304322101423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 4304322101423 its reverse (3241012234034), we get a palindrome (7545334335457).
The spelling of 4304322101423 in words is "four trillion, three hundred four billion, three hundred twenty-two million, one hundred one thousand, four hundred twenty-three".
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