43050044113 has 2 divisors, whose sum is σ = 43050044114. Its totient is φ = 43050044112.

The previous prime is 43050044053. The next prime is 43050044123. The reversal of 43050044113 is 31144005034.

43050044113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30552592849 + 12497451264 = 174793^2 + 111792^2 .

It is a cyclic number.

It is not a de Polignac number, because 43050044113 - 2¹³ = 43050035921 is a prime.

It is not a weakly prime, because it can be changed into another prime (43050044123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21525022056 + 21525022057.

It is an arithmetic number, because the mean of its divisors is an integer number (21525022057).

Almost surely, 2^43050044113 is an apocalyptic number.

It is an amenable number.

43050044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43050044113 is an equidigital number, since it uses as much as digits as its factorization.

43050044113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 43050044113 its reverse (31144005034), we get a palindrome (74194049147).

The spelling of 43050044113 in words is "forty-three billion, fifty million, forty-four thousand, one hundred thirteen".