43051131031 has 2 divisors, whose sum is σ = 43051131032. Its totient is φ = 43051131030.

The previous prime is 43051130971. The next prime is 43051131043. The reversal of 43051131031 is 13013115034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43051131031 - 2²⁵ = 43017576599 is a prime.

It is a super-2 number, since 2×43051131031² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43051130993 and 43051131011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43051131131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21525565515 + 21525565516.

It is an arithmetic number, because the mean of its divisors is an integer number (21525565516).

Almost surely, 2^43051131031 is an apocalyptic number.

43051131031 is a deficient number, since it is larger than the sum of its proper divisors (1).

43051131031 is an equidigital number, since it uses as much as digits as its factorization.

43051131031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 43051131031 its reverse (13013115034), we get a palindrome (56064246065).

The spelling of 43051131031 in words is "forty-three billion, fifty-one million, one hundred thirty-one thousand, thirty-one".