Base | Representation |
---|---|
bin | 101000001000111101… |
… | …111010010001001111 |
3 | 11010020201110221212001 |
4 | 220020331322101033 |
5 | 1201232112321033 |
6 | 31444441053131 |
7 | 3054026655643 |
oct | 501075722117 |
9 | 133221427761 |
10 | 43100120143 |
11 | 17307992203 |
12 | 842a1871a7 |
13 | 40ab420192 |
14 | 212c1d6c23 |
15 | 11c3c55e7d |
hex | a08f7a44f |
43100120143 has 2 divisors, whose sum is σ = 43100120144. Its totient is φ = 43100120142.
The previous prime is 43100120123. The next prime is 43100120153. The reversal of 43100120143 is 34102100134.
43100120143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43100120143 - 217 = 43099989071 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 43100120143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43100120123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21550060071 + 21550060072.
It is an arithmetic number, because the mean of its divisors is an integer number (21550060072).
Almost surely, 243100120143 is an apocalyptic number.
43100120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
43100120143 is an equidigital number, since it uses as much as digits as its factorization.
43100120143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 43100120143 its reverse (34102100134), we get a palindrome (77202220277).
The spelling of 43100120143 in words is "forty-three billion, one hundred million, one hundred twenty thousand, one hundred forty-three".
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