Base | Representation |
---|---|
bin | 10011100110011111110101… |
… | …01110111000101111110111 |
3 | 12122121201111001022000002211 |
4 | 21303033322232320233313 |
5 | 21122204402033113143 |
6 | 231401444144314251 |
7 | 12036114225503161 |
oct | 1163177256705767 |
9 | 178551431260084 |
10 | 43104203410423 |
11 | 12809432112361 |
12 | 4a01a72612987 |
13 | 1b0892a7081ac |
14 | a9037c7b5931 |
15 | 4eb38c70049d |
hex | 2733fabb8bf7 |
43104203410423 has 2 divisors, whose sum is σ = 43104203410424. Its totient is φ = 43104203410422.
The previous prime is 43104203410393. The next prime is 43104203410447. The reversal of 43104203410423 is 32401430240134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43104203410423 - 25 = 43104203410391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43104203410223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21552101705211 + 21552101705212.
It is an arithmetic number, because the mean of its divisors is an integer number (21552101705212).
Almost surely, 243104203410423 is an apocalyptic number.
43104203410423 is a deficient number, since it is larger than the sum of its proper divisors (1).
43104203410423 is an equidigital number, since it uses as much as digits as its factorization.
43104203410423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 43104203410423 its reverse (32401430240134), we get a palindrome (75505633650557).
The spelling of 43104203410423 in words is "forty-three trillion, one hundred four billion, two hundred three million, four hundred ten thousand, four hundred twenty-three".
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