Base | Representation |
---|---|
bin | 1100100010111001110… |
… | …00011111011101100001 |
3 | 1112012121222002222110102 |
4 | 12101130320133131201 |
5 | 24030300042324101 |
6 | 530005101312145 |
7 | 43066642256144 |
oct | 6213470373541 |
9 | 1465558088412 |
10 | 431055042401 |
11 | 15689a3743a5 |
12 | 6b65b565655 |
13 | 31857472b89 |
14 | 16c127a605b |
15 | b32ce7786b |
hex | 645ce1f761 |
431055042401 has 2 divisors, whose sum is σ = 431055042402. Its totient is φ = 431055042400.
The previous prime is 431055042361. The next prime is 431055042403. The reversal of 431055042401 is 104240550134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 355430592400 + 75624450001 = 596180^2 + 274999^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-431055042401 is a prime.
Together with 431055042403, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (431055042403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215527521200 + 215527521201.
It is an arithmetic number, because the mean of its divisors is an integer number (215527521201).
Almost surely, 2431055042401 is an apocalyptic number.
It is an amenable number.
431055042401 is a deficient number, since it is larger than the sum of its proper divisors (1).
431055042401 is an equidigital number, since it uses as much as digits as its factorization.
431055042401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 431055042401 its reverse (104240550134), we get a palindrome (535295592535).
The spelling of 431055042401 in words is "four hundred thirty-one billion, fifty-five million, forty-two thousand, four hundred one".
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