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431055153122021 is a prime number
BaseRepresentation
bin110001000000010101101100…
…1010001111100101011100101
32002112020110200202201012012222
41202000223121101330223211
5422444401423144401041
64124440000435322125
7156536464351022651
oct14200533121745345
92075213622635188
10431055153122021
1111539051139751a
1240419462750345
131566a4324a707c
147863275ccba61
1534c7b0161474b
hex1880ad947cae5

431055153122021 has 2 divisors, whose sum is σ = 431055153122022. Its totient is φ = 431055153122020.

The previous prime is 431055153122017. The next prime is 431055153122063. The reversal of 431055153122021 is 120221351550134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 292199331757921 + 138855821364100 = 17093839^2 + 11783710^2 .

It is a cyclic number.

It is not a de Polignac number, because 431055153122021 - 22 = 431055153122017 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431055153122081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215527576561010 + 215527576561011.

It is an arithmetic number, because the mean of its divisors is an integer number (215527576561011).

Almost surely, 2431055153122021 is an apocalyptic number.

It is an amenable number.

431055153122021 is a deficient number, since it is larger than the sum of its proper divisors (1).

431055153122021 is an equidigital number, since it uses as much as digits as its factorization.

431055153122021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 431055153122021 in words is "four hundred thirty-one trillion, fifty-five billion, one hundred fifty-three million, one hundred twenty-two thousand, twenty-one".