Base | Representation |
---|---|
bin | 1100100010111010001… |
… | …11000001000101001001 |
3 | 1112012122020021102200002 |
4 | 12101131013001011021 |
5 | 24030302031200441 |
6 | 530005315052345 |
7 | 43100016525314 |
oct | 6213507010511 |
9 | 1465566242602 |
10 | 431058850121 |
11 | 1568a1535179 |
12 | 6b6608a10b5 |
13 | 318581a7073 |
14 | 16c130b797b |
15 | b32d47ab9b |
hex | 645d1c1149 |
431058850121 has 2 divisors, whose sum is σ = 431058850122. Its totient is φ = 431058850120.
The previous prime is 431058850093. The next prime is 431058850153. The reversal of 431058850121 is 121058850134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 263106417721 + 167952432400 = 512939^2 + 409820^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-431058850121 is a prime.
It is a super-3 number, since 3×4310588501213 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (431058850721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215529425060 + 215529425061.
It is an arithmetic number, because the mean of its divisors is an integer number (215529425061).
Almost surely, 2431058850121 is an apocalyptic number.
It is an amenable number.
431058850121 is a deficient number, since it is larger than the sum of its proper divisors (1).
431058850121 is an equidigital number, since it uses as much as digits as its factorization.
431058850121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 38.
The spelling of 431058850121 in words is "four hundred thirty-one billion, fifty-eight million, eight hundred fifty thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •