Base | Representation |
---|---|
bin | 110001000000101011010000… |
… | …0011100000001010000001101 |
3 | 2002112101220011212100120200211 |
4 | 1202001112200130001100031 |
5 | 423001131224142214013 |
6 | 4124513134103522421 |
7 | 156543023444610511 |
oct | 14201264034012015 |
9 | 2075356155316624 |
10 | 431101444101133 |
11 | 1153a9106449253 |
12 | 40426421459411 |
13 | 156718cb9b5180 |
14 | 78655c7bb0141 |
15 | 34c8e1056023d |
hex | 18815a070140d |
431101444101133 has 8 divisors (see below), whose sum is σ = 464266986975288. Its totient is φ = 397936457416704.
The previous prime is 431101444101103. The next prime is 431101444101137. The reversal of 431101444101133 is 331101444101134.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 54561312952969 + 376540131148164 = 7386563^2 + 19404642^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 431101444101133 - 213 = 431101444092941 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 431101444101095 and 431101444101104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (431101444101137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 137436916 + ... + 140538637.
It is an arithmetic number, because the mean of its divisors is an integer number (58033373371911).
Almost surely, 2431101444101133 is an apocalyptic number.
It is an amenable number.
431101444101133 is a deficient number, since it is larger than the sum of its proper divisors (33165542874155).
431101444101133 is a wasteful number, since it uses less digits than its factorization.
431101444101133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 278094863.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 431101444101133 its reverse (331101444101134), we get a palindrome (762202888202267).
Subtracting from 431101444101133 its reverse (331101444101134), we obtain a palindrome (99999999999999).
The spelling of 431101444101133 in words is "four hundred thirty-one trillion, one hundred one billion, four hundred forty-four million, one hundred one thousand, one hundred thirty-three".
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