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431111222111231 is a prime number
BaseRepresentation
bin110001000000101111110011…
…1010000001010101111111111
32002112102211102022101221220222
41202001133213100022233333
5423001311240330024411
64124521432240331555
7156543520655410544
oct14201374720125777
92075384368357828
10431111222111231
11115402273920a32
12404282b0013bbb
13156727c96b926c
147865c74668bcb
1534c92d3bbd4db
hex18817e740abff

431111222111231 has 2 divisors, whose sum is σ = 431111222111232. Its totient is φ = 431111222111230.

The previous prime is 431111222111071. The next prime is 431111222111237. The reversal of 431111222111231 is 132111222111134.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-431111222111231 is a prime.

It is a super-2 number, since 2×4311112221112312 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 431111222111231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431111222111237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215555611055615 + 215555611055616.

It is an arithmetic number, because the mean of its divisors is an integer number (215555611055616).

Almost surely, 2431111222111231 is an apocalyptic number.

431111222111231 is a deficient number, since it is larger than the sum of its proper divisors (1).

431111222111231 is an equidigital number, since it uses as much as digits as its factorization.

431111222111231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 26.

Adding to 431111222111231 its reverse (132111222111134), we get a palindrome (563222444222365).

The spelling of 431111222111231 in words is "four hundred thirty-one trillion, one hundred eleven billion, two hundred twenty-two million, one hundred eleven thousand, two hundred thirty-one".