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431123143412231 is a prime number
BaseRepresentation
bin110001000000110101010110…
…1110100010100101000000111
32002112110222012010102210112122
41202001222231310110220013
5423002010144203142411
64124531123215240155
7156544422252660254
oct14201525564245007
92075428163383478
10431123143412231
1111540733110a906
124042a67851905b
131567397945791a
147866685a3c42b
1534c97805959db
hex1881aadd14a07

431123143412231 has 2 divisors, whose sum is σ = 431123143412232. Its totient is φ = 431123143412230.

The previous prime is 431123143412207. The next prime is 431123143412261. The reversal of 431123143412231 is 132214341321134.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-431123143412231 is a prime.

It is a super-2 number, since 2×4311231434122312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 431123143412191 and 431123143412200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (431123143412261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215561571706115 + 215561571706116.

It is an arithmetic number, because the mean of its divisors is an integer number (215561571706116).

Almost surely, 2431123143412231 is an apocalyptic number.

431123143412231 is a deficient number, since it is larger than the sum of its proper divisors (1).

431123143412231 is an equidigital number, since it uses as much as digits as its factorization.

431123143412231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 35.

Adding to 431123143412231 its reverse (132214341321134), we get a palindrome (563337484733365).

The spelling of 431123143412231 in words is "four hundred thirty-one trillion, one hundred twenty-three billion, one hundred forty-three million, four hundred twelve thousand, two hundred thirty-one".