43113111424303 has 2 divisors, whose sum is σ = 43113111424304. Its totient is φ = 43113111424302.

The previous prime is 43113111424289. The next prime is 43113111424307. The reversal of 43113111424303 is 30342411131134.

43113111424303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43113111424303 - 2⁹ = 43113111423791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43113111424307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21556555712151 + 21556555712152.

It is an arithmetic number, because the mean of its divisors is an integer number (21556555712152).

Almost surely, 2^{43113111424303} is an apocalyptic number.

43113111424303 is a deficient number, since it is larger than the sum of its proper divisors (1).

43113111424303 is an equidigital number, since it uses as much as digits as its factorization.

43113111424303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 43113111424303 its reverse (30342411131134), we get a palindrome (73455522555437).

The spelling of 43113111424303 in words is "forty-three trillion, one hundred thirteen billion, one hundred eleven million, four hundred twenty-four thousand, three hundred three".