4311312302041 has 2 divisors, whose sum is σ = 4311312302042. Its totient is φ = 4311312302040.

The previous prime is 4311312301999. The next prime is 4311312302053. The reversal of 4311312302041 is 1402032131134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4109657418441 + 201654883600 = 2027229^2 + 449060^2 .

It is a cyclic number.

It is not a de Polignac number, because 4311312302041 - 2¹¹ = 4311312299993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4311312301997 and 4311312302015.

It is not a weakly prime, because it can be changed into another prime (4311312302071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155656151020 + 2155656151021.

It is an arithmetic number, because the mean of its divisors is an integer number (2155656151021).

Almost surely, 2^{4311312302041} is an apocalyptic number.

It is an amenable number.

4311312302041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311312302041 is an equidigital number, since it uses as much as digits as its factorization.

4311312302041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4311312302041 its reverse (1402032131134), we get a palindrome (5713344433175).

The spelling of 4311312302041 in words is "four trillion, three hundred eleven billion, three hundred twelve million, three hundred two thousand, forty-one".