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43113202241 is a prime number
BaseRepresentation
bin101000001001101111…
…110100001001000001
311010021122002121010012
4220021233310021001
51201243434432431
631450025314305
73054246113114
oct501157641101
9133248077105
1043113202241
1117314307a5a
128432635995
1340b1050875
14212dc4057b
1511c4e8c22b
hexa09bf4241

43113202241 has 2 divisors, whose sum is σ = 43113202242. Its totient is φ = 43113202240.

The previous prime is 43113202217. The next prime is 43113202243. The reversal of 43113202241 is 14220231134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22953462016 + 20159740225 = 151504^2 + 141985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43113202241 is a prime.

Together with 43113202243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (43113202243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21556601120 + 21556601121.

It is an arithmetic number, because the mean of its divisors is an integer number (21556601121).

Almost surely, 243113202241 is an apocalyptic number.

It is an amenable number.

43113202241 is a deficient number, since it is larger than the sum of its proper divisors (1).

43113202241 is an equidigital number, since it uses as much as digits as its factorization.

43113202241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 43113202241 its reverse (14220231134), we get a palindrome (57333433375).

The spelling of 43113202241 in words is "forty-three billion, one hundred thirteen million, two hundred two thousand, two hundred forty-one".