Base | Representation |
---|---|
bin | 101000001001110000… |
… | …101100000001100111 |
3 | 11010021122112020010001 |
4 | 220021300230001213 |
5 | 1201244014244033 |
6 | 31450034242131 |
7 | 3054251055346 |
oct | 501160540147 |
9 | 133248466101 |
10 | 43113431143 |
11 | 17314453a32 |
12 | 8432726347 |
13 | 40b1100b03 |
14 | 212dc9db5d |
15 | 11c4ed4e7d |
hex | a09c2c067 |
43113431143 has 2 divisors, whose sum is σ = 43113431144. Its totient is φ = 43113431142.
The previous prime is 43113431113. The next prime is 43113431147. The reversal of 43113431143 is 34113431134.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43113431143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43113431147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21556715571 + 21556715572.
It is an arithmetic number, because the mean of its divisors is an integer number (21556715572).
Almost surely, 243113431143 is an apocalyptic number.
43113431143 is a deficient number, since it is larger than the sum of its proper divisors (1).
43113431143 is an equidigital number, since it uses as much as digits as its factorization.
43113431143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 43113431143 its reverse (34113431134), we get a palindrome (77226862277).
Subtracting from 43113431143 its reverse (34113431134), we obtain a palindrome (9000000009).
The spelling of 43113431143 in words is "forty-three billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred forty-three".
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