Base | Representation |
---|---|
bin | 110001000001011111010010… |
… | …1101111110000101111000110 |
3 | 2002112210120122111010221010212 |
4 | 1202002332211233300233012 |
5 | 423004444114242442014 |
6 | 4125040335502115422 |
7 | 156554061065666534 |
oct | 14202764557605706 |
9 | 2075716574127125 |
10 | 431213202312134 |
11 | 115441546000300 |
12 | 40444010b7bb72 |
13 | 1567c2cc5301c8 |
14 | 786ab8a6ad154 |
15 | 34cbca1ba923e |
hex | 1882fa5bf0bc6 |
431213202312134 has 48 divisors (see below), whose sum is σ = 717968176467360. Its totient is φ = 194076434851200.
The previous prime is 431213202312131. The next prime is 431213202312169.
431213202312134 is nontrivially palindromic in base 10.
It is a self number, because there is not a number n which added to its sum of digits gives 431213202312134.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (431213202312131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 181301732 + ... + 183664760.
It is an arithmetic number, because the mean of its divisors is an integer number (14957670343070).
Almost surely, 2431213202312134 is an apocalyptic number.
431213202312134 is a deficient number, since it is larger than the sum of its proper divisors (286754974155226).
431213202312134 is a wasteful number, since it uses less digits than its factorization.
431213202312134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2370477 (or 2370466 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
It can be divided in two parts, 43121320 and 2312134, that added together give a palindrome (45433454).
The spelling of 431213202312134 in words is "four hundred thirty-one trillion, two hundred thirteen billion, two hundred two million, three hundred twelve thousand, one hundred thirty-four".
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