Base | Representation |
---|---|
bin | 111110110000000101000… |
… | …100001000001000011111 |
3 | 120021020121212112110211211 |
4 | 332300011010020020133 |
5 | 1031122422411230101 |
6 | 13101002340125251 |
7 | 623356063231315 |
oct | 76600504101037 |
9 | 16236555473754 |
10 | 4312232133151 |
11 | 141289768a618 |
12 | 5978a5996827 |
13 | 253845bb7047 |
14 | 10c9dac480b5 |
15 | 7728748ec51 |
hex | 3ec0510821f |
4312232133151 has 2 divisors, whose sum is σ = 4312232133152. Its totient is φ = 4312232133150.
The previous prime is 4312232133113. The next prime is 4312232133163. The reversal of 4312232133151 is 1513312322134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4312232133151 - 239 = 3762476319263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4312232137151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156116066575 + 2156116066576.
It is an arithmetic number, because the mean of its divisors is an integer number (2156116066576).
Almost surely, 24312232133151 is an apocalyptic number.
4312232133151 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312232133151 is an equidigital number, since it uses as much as digits as its factorization.
4312232133151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 31.
Adding to 4312232133151 its reverse (1513312322134), we get a palindrome (5825544455285).
The spelling of 4312232133151 in words is "four trillion, three hundred twelve billion, two hundred thirty-two million, one hundred thirty-three thousand, one hundred fifty-one".
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