Base | Representation |
---|---|
bin | 111110110000000101101… |
… | …101111110000100110001 |
3 | 120021020122122011202021112 |
4 | 332300011231332010301 |
5 | 1031122433213231001 |
6 | 13101003411203105 |
7 | 623356255404422 |
oct | 76600555760461 |
9 | 16236578152245 |
10 | 4312243102001 |
11 | 14128a28a168a |
12 | 5978a95a6495 |
13 | 2538482578a3 |
14 | 10c9dc4a1649 |
15 | 77288409cbb |
hex | 3ec05b7e131 |
4312243102001 has 2 divisors, whose sum is σ = 4312243102002. Its totient is φ = 4312243102000.
The previous prime is 4312243101977. The next prime is 4312243102021. The reversal of 4312243102001 is 1002013422134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4063546398976 + 248696703025 = 2015824^2 + 498695^2 .
It is a cyclic number.
It is not a de Polignac number, because 4312243102001 - 214 = 4312243085617 is a prime.
It is not a weakly prime, because it can be changed into another prime (4312243102021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156121551000 + 2156121551001.
It is an arithmetic number, because the mean of its divisors is an integer number (2156121551001).
Almost surely, 24312243102001 is an apocalyptic number.
It is an amenable number.
4312243102001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312243102001 is an equidigital number, since it uses as much as digits as its factorization.
4312243102001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4312243102001 its reverse (1002013422134), we get a palindrome (5314256524135).
The spelling of 4312243102001 in words is "four trillion, three hundred twelve billion, two hundred forty-three million, one hundred two thousand, one".
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