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4312243102021 is a prime number
BaseRepresentation
bin111110110000000101101…
…101111110000101000101
3120021020122122011202022021
4332300011231332011011
51031122433213231041
613101003411203141
7623356255404451
oct76600555760505
916236578152267
104312243102021
1114128a28a16a8
125978a95a64b1
132538482578ba
1410c9dc4a1661
1577288409cd1
hex3ec05b7e145

4312243102021 has 2 divisors, whose sum is σ = 4312243102022. Its totient is φ = 4312243102020.

The previous prime is 4312243102001. The next prime is 4312243102049. The reversal of 4312243102021 is 1202013422134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4264592577921 + 47650524100 = 2065089^2 + 218290^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312243102021 - 211 = 4312243099973 is a prime.

It is a super-2 number, since 2×43122431020212 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4312243102001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156121551010 + 2156121551011.

It is an arithmetic number, because the mean of its divisors is an integer number (2156121551011).

Almost surely, 24312243102021 is an apocalyptic number.

It is an amenable number.

4312243102021 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312243102021 is an equidigital number, since it uses as much as digits as its factorization.

4312243102021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4312243102021 its reverse (1202013422134), we get a palindrome (5514256524155).

The spelling of 4312243102021 in words is "four trillion, three hundred twelve billion, two hundred forty-three million, one hundred two thousand, twenty-one".