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4312404110041 is a prime number
BaseRepresentation
bin111110110000001111010…
…100001010101011011001
3120021021001212010210210021
4332300033110022223121
51031123300423010131
613101031402150441
7623363252062546
oct76601724125331
916237055123707
104312404110041
111412975772385
125979334b2421
1325387270c111
1410ca15a13bcd
1577297610e11
hex3ec0f50aad9

4312404110041 has 2 divisors, whose sum is σ = 4312404110042. Its totient is φ = 4312404110040.

The previous prime is 4312404109991. The next prime is 4312404110057. The reversal of 4312404110041 is 1400114042134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4135671313225 + 176732796816 = 2033635^2 + 420396^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312404110041 - 213 = 4312404101849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4312404109988 and 4312404110015.

It is not a weakly prime, because it can be changed into another prime (4312404110071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156202055020 + 2156202055021.

It is an arithmetic number, because the mean of its divisors is an integer number (2156202055021).

Almost surely, 24312404110041 is an apocalyptic number.

It is an amenable number.

4312404110041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312404110041 is an equidigital number, since it uses as much as digits as its factorization.

4312404110041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4312404110041 its reverse (1400114042134), we get a palindrome (5712518152175).

The spelling of 4312404110041 in words is "four trillion, three hundred twelve billion, four hundred four million, one hundred ten thousand, forty-one".