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43125100117 = 119740417151
BaseRepresentation
bin101000001010011101…
…001100111001010101
311010022110111001221021
4220022131030321111
51201310011200432
631451132321141
73054452205601
oct501235147125
9133273431837
1043125100117
111731aaa4010
1284366131b1
1340b3658228
14213165a501
1511c603c697
hexa0a74ce55

43125100117 has 8 divisors (see below), whose sum is σ = 47530570752. Its totient is φ = 38800464000.

The previous prime is 43125100111. The next prime is 43125100121. The reversal of 43125100117 is 71100152134.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 43125100117 - 231 = 40977616469 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43125100091 and 43125100100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43125100111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20207509 + ... + 20209642.

It is an arithmetic number, because the mean of its divisors is an integer number (5941321344).

Almost surely, 243125100117 is an apocalyptic number.

It is an amenable number.

43125100117 is a deficient number, since it is larger than the sum of its proper divisors (4405470635).

43125100117 is a wasteful number, since it uses less digits than its factorization.

43125100117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40417259.

The product of its (nonzero) digits is 840, while the sum is 25.

The spelling of 43125100117 in words is "forty-three billion, one hundred twenty-five million, one hundred thousand, one hundred seventeen".

Divisors: 1 11 97 1067 40417151 444588661 3920463647 43125100117