Base | Representation |
---|---|
bin | 10011100111001111111100… |
… | …01001000111110011010011 |
3 | 12122201012010222101012020111 |
4 | 21303213332021013303103 |
5 | 21123120300242021001 |
6 | 231421355031022151 |
7 | 12041020234465522 |
oct | 1163477611076323 |
9 | 178635128335214 |
10 | 43130030423251 |
11 | 1281938585a362 |
12 | 4a06a7bb0a957 |
13 | 1b0b1b53919c5 |
14 | a9170c91a4b9 |
15 | 4ebd9ecd3851 |
hex | 2739fe247cd3 |
43130030423251 has 2 divisors, whose sum is σ = 43130030423252. Its totient is φ = 43130030423250.
The previous prime is 43130030423213. The next prime is 43130030423303. The reversal of 43130030423251 is 15232403003134.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43130030423251 - 217 = 43130030292179 is a prime.
It is not a weakly prime, because it can be changed into another prime (43130030420251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21565015211625 + 21565015211626.
It is an arithmetic number, because the mean of its divisors is an integer number (21565015211626).
Almost surely, 243130030423251 is an apocalyptic number.
43130030423251 is a deficient number, since it is larger than the sum of its proper divisors (1).
43130030423251 is an equidigital number, since it uses as much as digits as its factorization.
43130030423251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 43130030423251 its reverse (15232403003134), we get a palindrome (58362433426385).
The spelling of 43130030423251 in words is "forty-three trillion, one hundred thirty billion, thirty million, four hundred twenty-three thousand, two hundred fifty-one".
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