Base | Representation |
---|---|
bin | 10011100111001111111101… |
… | …10010010100010011111111 |
3 | 12122201012011201200211212221 |
4 | 21303213332302110103333 |
5 | 21123120311023104044 |
6 | 231421400054310211 |
7 | 12041020425334105 |
oct | 1163477662242377 |
9 | 178635151624787 |
10 | 43130041222399 |
11 | 1281939096597a |
12 | 4a06a83658367 |
13 | 1b0b1b76a3231 |
14 | a9171012bc75 |
15 | 4ebda0c18484 |
hex | 2739fec944ff |
43130041222399 has 2 divisors, whose sum is σ = 43130041222400. Its totient is φ = 43130041222398.
The previous prime is 43130041222351. The next prime is 43130041222421. The reversal of 43130041222399 is 99322214003134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43130041222399 - 217 = 43130041091327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43130041222999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21565020611199 + 21565020611200.
It is an arithmetic number, because the mean of its divisors is an integer number (21565020611200).
Almost surely, 243130041222399 is an apocalyptic number.
43130041222399 is a deficient number, since it is larger than the sum of its proper divisors (1).
43130041222399 is an equidigital number, since it uses as much as digits as its factorization.
43130041222399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 43.
The spelling of 43130041222399 in words is "forty-three trillion, one hundred thirty billion, forty-one million, two hundred twenty-two thousand, three hundred ninety-nine".
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