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43130114341 = 311391294011
BaseRepresentation
bin101000001010110000…
…010101000100100101
311010022210220211011021
4220022300111010211
51201312302124331
631451432011141
73054542631406
oct501260250445
9133283824137
1043130114341
11173229092a6
128438230ab1
1340b46c2622
1421321a39ad
1511c66cd211
hexa0ac15125

43130114341 has 4 divisors (see below), whose sum is σ = 44521408384. Its totient is φ = 41738820300.

The previous prime is 43130114317. The next prime is 43130114351. The reversal of 43130114341 is 14341103134.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43130114341 - 217 = 43129983269 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43130114351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 695646975 + ... + 695647036.

It is an arithmetic number, because the mean of its divisors is an integer number (11130352096).

Almost surely, 243130114341 is an apocalyptic number.

It is an amenable number.

43130114341 is a deficient number, since it is larger than the sum of its proper divisors (1391294043).

43130114341 is a wasteful number, since it uses less digits than its factorization.

43130114341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1391294042.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 43130114341 its reverse (14341103134), we get a palindrome (57471217475).

The spelling of 43130114341 in words is "forty-three billion, one hundred thirty million, one hundred fourteen thousand, three hundred forty-one".

Divisors: 1 31 1391294011 43130114341