Base | Representation |
---|---|
bin | 111110110000111111111… |
… | …101011111101001011001 |
3 | 120021100011201212000121121 |
4 | 332300333331133221121 |
5 | 1031131433341001301 |
6 | 13101244355005241 |
7 | 623422422131122 |
oct | 76607775375131 |
9 | 16240151760547 |
10 | 4313220250201 |
11 | 1413254427585 |
12 | 597b20899821 |
13 | 2539728235a5 |
14 | 10ca92181049 |
15 | 772e40c53a1 |
hex | 3ec3ff5fa59 |
4313220250201 has 2 divisors, whose sum is σ = 4313220250202. Its totient is φ = 4313220250200.
The previous prime is 4313220250189. The next prime is 4313220250319. The reversal of 4313220250201 is 1020520223134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2802865278976 + 1510354971225 = 1674176^2 + 1228965^2 .
It is a cyclic number.
It is not a de Polignac number, because 4313220250201 - 211 = 4313220248153 is a prime.
It is not a weakly prime, because it can be changed into another prime (4313220250601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156610125100 + 2156610125101.
It is an arithmetic number, because the mean of its divisors is an integer number (2156610125101).
Almost surely, 24313220250201 is an apocalyptic number.
It is an amenable number.
4313220250201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4313220250201 is an equidigital number, since it uses as much as digits as its factorization.
4313220250201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 4313220250201 its reverse (1020520223134), we get a palindrome (5333740473335).
The spelling of 4313220250201 in words is "four trillion, three hundred thirteen billion, two hundred twenty million, two hundred fifty thousand, two hundred one".
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