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431325481 is a prime number
BaseRepresentation
bin11001101101011…
…000000100101001
31010001121121022211
4121231120010221
51340404403411
6110444445121
713455130456
oct3155300451
91101547284
10431325481
11201521244
121005497a1
136b48b9a2
14413da82d
1527d00221
hex19b58129

431325481 has 2 divisors, whose sum is σ = 431325482. Its totient is φ = 431325480.

The previous prime is 431325469. The next prime is 431325493. The reversal of 431325481 is 184523134.

It is a balanced prime because it is at equal distance from previous prime (431325469) and next prime (431325493).

It can be written as a sum of positive squares in only one way, i.e., 408848400 + 22477081 = 20220^2 + 4741^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-431325481 is a prime.

It is a super-2 number, since 2×4313254812 = 372083341119762722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (431326481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215662740 + 215662741.

It is an arithmetic number, because the mean of its divisors is an integer number (215662741).

Almost surely, 2431325481 is an apocalyptic number.

It is an amenable number.

431325481 is a deficient number, since it is larger than the sum of its proper divisors (1).

431325481 is an equidigital number, since it uses as much as digits as its factorization.

431325481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 31.

The square root of 431325481 is about 20768.3769466947. The cubic root of 431325481 is about 755.5589802236.

The spelling of 431325481 in words is "four hundred thirty-one million, three hundred twenty-five thousand, four hundred eighty-one".