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431329927481 is a prime number
BaseRepresentation
bin1100100011011010100…
…01000110000100111001
31112020100010100120220022
412101231101012010321
524031330430134411
6530052241140225
743106520614315
oct6215521060471
91466303316808
10431329927481
11156a20554652
126b71762a675
133189c3b937b
1416c3b0bcb45
15b347174edb
hex646d446139

431329927481 has 2 divisors, whose sum is σ = 431329927482. Its totient is φ = 431329927480.

The previous prime is 431329927477. The next prime is 431329927513. The reversal of 431329927481 is 184729923134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 300184547881 + 131145379600 = 547891^2 + 362140^2 .

It is a cyclic number.

It is not a de Polignac number, because 431329927481 - 22 = 431329927477 is a prime.

It is a super-2 number, since 2×4313299274812 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (431329927411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215664963740 + 215664963741.

It is an arithmetic number, because the mean of its divisors is an integer number (215664963741).

Almost surely, 2431329927481 is an apocalyptic number.

It is an amenable number.

431329927481 is a deficient number, since it is larger than the sum of its proper divisors (1).

431329927481 is an equidigital number, since it uses as much as digits as its factorization.

431329927481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2612736, while the sum is 53.

The spelling of 431329927481 in words is "four hundred thirty-one billion, three hundred twenty-nine million, nine hundred twenty-seven thousand, four hundred eighty-one".