Base | Representation |
---|---|
bin | 111110110001000110000… |
… | …111000010011001001001 |
3 | 120021100102220222100021021 |
4 | 332301012013002121021 |
5 | 1031132141243240423 |
6 | 13101302522112441 |
7 | 623425114044346 |
oct | 76610607023111 |
9 | 16240386870237 |
10 | 4313323415113 |
11 | 14132a768a939 |
12 | 597b4b34b721 |
13 | 25398b00480b |
14 | 10caa1b577cd |
15 | 772ed1a295d |
hex | 3ec461c2649 |
4313323415113 has 2 divisors, whose sum is σ = 4313323415114. Its totient is φ = 4313323415112.
The previous prime is 4313323415057. The next prime is 4313323415143. The reversal of 4313323415113 is 3115143233134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3138382316304 + 1174941098809 = 1771548^2 + 1083947^2 .
It is a cyclic number.
It is not a de Polignac number, because 4313323415113 - 29 = 4313323414601 is a prime.
It is not a weakly prime, because it can be changed into another prime (4313323415143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156661707556 + 2156661707557.
It is an arithmetic number, because the mean of its divisors is an integer number (2156661707557).
Almost surely, 24313323415113 is an apocalyptic number.
It is an amenable number.
4313323415113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4313323415113 is an equidigital number, since it uses as much as digits as its factorization.
4313323415113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 38880, while the sum is 34.
Adding to 4313323415113 its reverse (3115143233134), we get a palindrome (7428466648247).
The spelling of 4313323415113 in words is "four trillion, three hundred thirteen billion, three hundred twenty-three million, four hundred fifteen thousand, one hundred thirteen".
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