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4313323415113 is a prime number
BaseRepresentation
bin111110110001000110000…
…111000010011001001001
3120021100102220222100021021
4332301012013002121021
51031132141243240423
613101302522112441
7623425114044346
oct76610607023111
916240386870237
104313323415113
1114132a768a939
12597b4b34b721
1325398b00480b
1410caa1b577cd
15772ed1a295d
hex3ec461c2649

4313323415113 has 2 divisors, whose sum is σ = 4313323415114. Its totient is φ = 4313323415112.

The previous prime is 4313323415057. The next prime is 4313323415143. The reversal of 4313323415113 is 3115143233134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3138382316304 + 1174941098809 = 1771548^2 + 1083947^2 .

It is a cyclic number.

It is not a de Polignac number, because 4313323415113 - 29 = 4313323414601 is a prime.

It is not a weakly prime, because it can be changed into another prime (4313323415143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156661707556 + 2156661707557.

It is an arithmetic number, because the mean of its divisors is an integer number (2156661707557).

Almost surely, 24313323415113 is an apocalyptic number.

It is an amenable number.

4313323415113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4313323415113 is an equidigital number, since it uses as much as digits as its factorization.

4313323415113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 38880, while the sum is 34.

Adding to 4313323415113 its reverse (3115143233134), we get a palindrome (7428466648247).

The spelling of 4313323415113 in words is "four trillion, three hundred thirteen billion, three hundred twenty-three million, four hundred fifteen thousand, one hundred thirteen".