Base | Representation |
---|---|
bin | 101000001010111100… |
… | …010111100000100011 |
3 | 11010100000212010222102 |
4 | 220022330113200203 |
5 | 1201314104120201 |
6 | 31452023401015 |
7 | 3054611513624 |
oct | 501274274043 |
9 | 133300763872 |
10 | 43133270051 |
11 | 17324674223 |
12 | 84392b316b |
13 | 40b5258b01 |
14 | 2132785a4b |
15 | 11c6b0326b |
hex | a0af17823 |
43133270051 has 2 divisors, whose sum is σ = 43133270052. Its totient is φ = 43133270050.
The previous prime is 43133270023. The next prime is 43133270053. The reversal of 43133270051 is 15007233134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43133270051 - 222 = 43129075747 is a prime.
Together with 43133270053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 43133269996 and 43133270023.
It is not a weakly prime, because it can be changed into another prime (43133270053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21566635025 + 21566635026.
It is an arithmetic number, because the mean of its divisors is an integer number (21566635026).
Almost surely, 243133270051 is an apocalyptic number.
43133270051 is a deficient number, since it is larger than the sum of its proper divisors (1).
43133270051 is an equidigital number, since it uses as much as digits as its factorization.
43133270051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 29.
The spelling of 43133270051 in words is "forty-three billion, one hundred thirty-three million, two hundred seventy thousand, fifty-one".
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