Base | Representation |
---|---|
bin | 101000001010111100… |
… | …101000101100010001 |
3 | 11010100000222201112011 |
4 | 220022330220230101 |
5 | 1201314113343213 |
6 | 31452025102521 |
7 | 3054612226051 |
oct | 501274505421 |
9 | 133300881464 |
10 | 43133340433 |
11 | 17324712097 |
12 | 8439327a41 |
13 | 40b5281b61 |
14 | 21327a3561 |
15 | 11c6b1903d |
hex | a0af28b11 |
43133340433 has 2 divisors, whose sum is σ = 43133340434. Its totient is φ = 43133340432.
The previous prime is 43133340403. The next prime is 43133340487. The reversal of 43133340433 is 33404333134.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30311854609 + 12821485824 = 174103^2 + 113232^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43133340433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43133340395 and 43133340404.
It is not a weakly prime, because it can be changed into another prime (43133340403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21566670216 + 21566670217.
It is an arithmetic number, because the mean of its divisors is an integer number (21566670217).
Almost surely, 243133340433 is an apocalyptic number.
It is an amenable number.
43133340433 is a deficient number, since it is larger than the sum of its proper divisors (1).
43133340433 is an equidigital number, since it uses as much as digits as its factorization.
43133340433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 31.
Adding to 43133340433 its reverse (33404333134), we get a palindrome (76537673567).
The spelling of 43133340433 in words is "forty-three billion, one hundred thirty-three million, three hundred forty thousand, four hundred thirty-three".
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