4313455003841 has 2 divisors, whose sum is σ = 4313455003842. Its totient is φ = 4313455003840.

The previous prime is 4313455003733. The next prime is 4313455003843. The reversal of 4313455003841 is 1483005543134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4234009944241 + 79445059600 = 2057671^2 + 281860^2 .

It is a cyclic number.

It is not a de Polignac number, because 4313455003841 - 2¹⁸ = 4313454741697 is a prime.

It is a super-2 number, since 2×4313455003841² (a number of 26 digits) contains 22 as substring.

Together with 4313455003843, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4313455003843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156727501920 + 2156727501921.

It is an arithmetic number, because the mean of its divisors is an integer number (2156727501921).

Almost surely, 2^{4313455003841} is an apocalyptic number.

It is an amenable number.

4313455003841 is a deficient number, since it is larger than the sum of its proper divisors (1).

4313455003841 is an equidigital number, since it uses as much as digits as its factorization.

4313455003841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 41.

The spelling of 4313455003841 in words is "four trillion, three hundred thirteen billion, four hundred fifty-five million, three thousand, eight hundred forty-one".