Base | Representation |
---|---|
bin | 101000001011001010… |
… | …111011010101100011 |
3 | 11010100022001001121012 |
4 | 220023022323111203 |
5 | 1201321043234234 |
6 | 31452241251135 |
7 | 3054656121341 |
oct | 501312732543 |
9 | 133308031535 |
10 | 43137086819 |
11 | 17326840882 |
12 | 843a633aab |
13 | 40b5c94158 |
14 | 213309a991 |
15 | 11c71090ce |
hex | a0b2bb563 |
43137086819 has 2 divisors, whose sum is σ = 43137086820. Its totient is φ = 43137086818.
The previous prime is 43137086801. The next prime is 43137086821. The reversal of 43137086819 is 91868073134.
43137086819 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43137086819 - 216 = 43137021283 is a prime.
It is a super-2 number, since 2×431370868192 (a number of 22 digits) contains 22 as substring.
Together with 43137086821, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (43137086869) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21568543409 + 21568543410.
It is an arithmetic number, because the mean of its divisors is an integer number (21568543410).
Almost surely, 243137086819 is an apocalyptic number.
43137086819 is a deficient number, since it is larger than the sum of its proper divisors (1).
43137086819 is an equidigital number, since it uses as much as digits as its factorization.
43137086819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 43137086819 in words is "forty-three billion, one hundred thirty-seven million, eighty-six thousand, eight hundred nineteen".
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