Base | Representation |
---|---|
bin | 1100100011100010111… |
… | …01101010111101000001 |
3 | 1112020112000211120021121 |
4 | 12101301131222331001 |
5 | 24032001441124441 |
6 | 530103234152241 |
7 | 43111334220502 |
oct | 6216135527501 |
9 | 1466460746247 |
10 | 431400333121 |
11 | 156a5727242a |
12 | 6b737122681 |
13 | 318b0b6a704 |
14 | 16c465a8ba9 |
15 | b34d430dd1 |
hex | 647176af41 |
431400333121 has 2 divisors, whose sum is σ = 431400333122. Its totient is φ = 431400333120.
The previous prime is 431400333107. The next prime is 431400333139. The reversal of 431400333121 is 121333004134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 268390308096 + 163010025025 = 518064^2 + 403745^2 .
It is a cyclic number.
It is not a de Polignac number, because 431400333121 - 29 = 431400332609 is a prime.
It is a super-2 number, since 2×4314003331212 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (431400333151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215700166560 + 215700166561.
It is an arithmetic number, because the mean of its divisors is an integer number (215700166561).
Almost surely, 2431400333121 is an apocalyptic number.
It is an amenable number.
431400333121 is a deficient number, since it is larger than the sum of its proper divisors (1).
431400333121 is an equidigital number, since it uses as much as digits as its factorization.
431400333121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 431400333121 its reverse (121333004134), we get a palindrome (552733337255).
The spelling of 431400333121 in words is "four hundred thirty-one billion, four hundred million, three hundred thirty-three thousand, one hundred twenty-one".
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