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431401113331 is a prime number
BaseRepresentation
bin1100100011100011000…
…00101001011011110011
31112020112002022012112021
412101301200221123303
524032002141111311
6530103303012311
743111343650246
oct6216140513363
91466462265467
10431401113331
11156a57755631
126b73743a097
13318b1081886
1416c4672d25d
15b34d537171
hex64718296f3

431401113331 has 2 divisors, whose sum is σ = 431401113332. Its totient is φ = 431401113330.

The previous prime is 431401113301. The next prime is 431401113379. The reversal of 431401113331 is 133311104134.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 431401113331 - 221 = 431399016179 is a prime.

It is a super-2 number, since 2×4314011133312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 431401113296 and 431401113305.

It is not a weakly prime, because it can be changed into another prime (431401113301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215700556665 + 215700556666.

It is an arithmetic number, because the mean of its divisors is an integer number (215700556666).

Almost surely, 2431401113331 is an apocalyptic number.

431401113331 is a deficient number, since it is larger than the sum of its proper divisors (1).

431401113331 is an equidigital number, since it uses as much as digits as its factorization.

431401113331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 431401113331 its reverse (133311104134), we get a palindrome (564712217465).

The spelling of 431401113331 in words is "four hundred thirty-one billion, four hundred one million, one hundred thirteen thousand, three hundred thirty-one".