Base | Representation |
---|---|
bin | 1000000010010001… |
… | …01011111000111001 |
3 | 102010122120222212121 |
4 | 10001020223320321 |
5 | 32313342141213 |
6 | 1552024241241 |
7 | 211622401651 |
oct | 40110537071 |
9 | 12118528777 |
10 | 4314021433 |
11 | 1914175177 |
12 | a04910221 |
13 | 5399bb607 |
14 | 2ccd37361 |
15 | 1a3b0388d |
hex | 10122be39 |
4314021433 has 2 divisors, whose sum is σ = 4314021434. Its totient is φ = 4314021432.
The previous prime is 4314021373. The next prime is 4314021449. The reversal of 4314021433 is 3341204134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4220841024 + 93180409 = 64968^2 + 9653^2 .
It is a cyclic number.
It is not a de Polignac number, because 4314021433 - 229 = 3777150521 is a prime.
It is a super-2 number, since 2×43140214332 = 37221561848766746978, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4314021398 and 4314021407.
It is not a weakly prime, because it can be changed into another prime (4314021463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157010716 + 2157010717.
It is an arithmetic number, because the mean of its divisors is an integer number (2157010717).
Almost surely, 24314021433 is an apocalyptic number.
It is an amenable number.
4314021433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4314021433 is an equidigital number, since it uses as much as digits as its factorization.
4314021433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
The square root of 4314021433 is about 65681.2106541894. The cubic root of 4314021433 is about 1627.8989116410.
Adding to 4314021433 its reverse (3341204134), we get a palindrome (7655225567).
The spelling of 4314021433 in words is "four billion, three hundred fourteen million, twenty-one thousand, four hundred thirty-three".
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