Base | Representation |
---|---|
bin | 10011100111100100100101… |
… | …01110100100111000011011 |
3 | 12122202020202100120210122212 |
4 | 21303302102232210320123 |
5 | 21123310444440014001 |
6 | 231430430453305335 |
7 | 12041562000536426 |
oct | 1163622256447033 |
9 | 178666670523585 |
10 | 43141113204251 |
11 | 128230527987a7 |
12 | 4a0905363524b |
13 | 1b0c2604b149a |
14 | a920807b89bd |
15 | 4ec2ecc757bb |
hex | 273c92ba4e1b |
43141113204251 has 2 divisors, whose sum is σ = 43141113204252. Its totient is φ = 43141113204250.
The previous prime is 43141113204173. The next prime is 43141113204257. The reversal of 43141113204251 is 15240231114134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43141113204251 - 238 = 42866235297307 is a prime.
It is a super-2 number, since 2×431411132042512 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43141113204257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570556602125 + 21570556602126.
It is an arithmetic number, because the mean of its divisors is an integer number (21570556602126).
Almost surely, 243141113204251 is an apocalyptic number.
43141113204251 is a deficient number, since it is larger than the sum of its proper divisors (1).
43141113204251 is an equidigital number, since it uses as much as digits as its factorization.
43141113204251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 43141113204251 its reverse (15240231114134), we get a palindrome (58381344318385).
The spelling of 43141113204251 in words is "forty-three trillion, one hundred forty-one billion, one hundred thirteen million, two hundred four thousand, two hundred fifty-one".
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