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43141213161877 is a prime number
BaseRepresentation
bin10011100111100100110001…
…01011111000100110010101
312122202021000022200011202011
421303302120223320212111
521123311201032140002
6231430444423544221
712041564323264165
oct1163623053704625
9178667008604664
1043141213161877
11128230a4160406
124a09080bbb071
131b0c27810b8cc
14a9208db985a5
154ec30691c8d7
hex273c98af8995

43141213161877 has 2 divisors, whose sum is σ = 43141213161878. Its totient is φ = 43141213161876.

The previous prime is 43141213161869. The next prime is 43141213161931. The reversal of 43141213161877 is 77816131214134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33730006524516 + 9411206637361 = 5807754^2 + 3067769^2 .

It is a cyclic number.

It is not a de Polignac number, because 43141213161877 - 23 = 43141213161869 is a prime.

It is a super-2 number, since 2×431412131618772 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 43141213161877.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43141213164877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570606580938 + 21570606580939.

It is an arithmetic number, because the mean of its divisors is an integer number (21570606580939).

Almost surely, 243141213161877 is an apocalyptic number.

It is an amenable number.

43141213161877 is a deficient number, since it is larger than the sum of its proper divisors (1).

43141213161877 is an equidigital number, since it uses as much as digits as its factorization.

43141213161877 is an evil number, because the sum of its binary digits is even.

The product of its digits is 677376, while the sum is 49.

The spelling of 43141213161877 in words is "forty-three trillion, one hundred forty-one billion, two hundred thirteen million, one hundred sixty-one thousand, eight hundred seventy-seven".