Base | Representation |
---|---|
bin | 101000001011100001… |
… | …100111100010100001 |
3 | 11010100201020021000201 |
4 | 220023201213202201 |
5 | 1201324104110131 |
6 | 31453012545201 |
7 | 3055060514161 |
oct | 501341474241 |
9 | 133321207021 |
10 | 43143035041 |
11 | 1732a133867 |
12 | 8440622201 |
13 | 40b7297702 |
14 | 2133ba85a1 |
15 | 11c78d1761 |
hex | a0b8678a1 |
43143035041 has 2 divisors, whose sum is σ = 43143035042. Its totient is φ = 43143035040.
The previous prime is 43143035003. The next prime is 43143035053. The reversal of 43143035041 is 14053034134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40724854416 + 2418180625 = 201804^2 + 49175^2 .
It is a cyclic number.
It is not a de Polignac number, because 43143035041 - 223 = 43134646433 is a prime.
It is a super-2 number, since 2×431430350412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43143035641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571517520 + 21571517521.
It is an arithmetic number, because the mean of its divisors is an integer number (21571517521).
Almost surely, 243143035041 is an apocalyptic number.
It is an amenable number.
43143035041 is a deficient number, since it is larger than the sum of its proper divisors (1).
43143035041 is an equidigital number, since it uses as much as digits as its factorization.
43143035041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 43143035041 its reverse (14053034134), we get a palindrome (57196069175).
The spelling of 43143035041 in words is "forty-three billion, one hundred forty-three million, thirty-five thousand, forty-one".
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