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43143035641 is a prime number
BaseRepresentation
bin101000001011100001…
…100111101011111001
311010100201020021211221
4220023201213223321
51201324104120031
631453012552041
73055060516006
oct501341475371
9133321207757
1043143035641
111732a134262
128440622621
1340b7297a74
142133ba88ad
1511c78d1a11
hexa0b867af9

43143035641 has 2 divisors, whose sum is σ = 43143035642. Its totient is φ = 43143035640.

The previous prime is 43143035633. The next prime is 43143035647. The reversal of 43143035641 is 14653034134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39370496400 + 3772539241 = 198420^2 + 61421^2 .

It is a cyclic number.

It is not a de Polignac number, because 43143035641 - 23 = 43143035633 is a prime.

It is a super-2 number, since 2×431430356412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43143035597 and 43143035606.

It is not a weakly prime, because it can be changed into another prime (43143035647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571517820 + 21571517821.

It is an arithmetic number, because the mean of its divisors is an integer number (21571517821).

Almost surely, 243143035641 is an apocalyptic number.

It is an amenable number.

43143035641 is a deficient number, since it is larger than the sum of its proper divisors (1).

43143035641 is an equidigital number, since it uses as much as digits as its factorization.

43143035641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 43143035641 its reverse (14653034134), we get a palindrome (57796069775).

The spelling of 43143035641 in words is "forty-three billion, one hundred forty-three million, thirty-five thousand, six hundred forty-one".