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4314311334257 is a prime number
BaseRepresentation
bin111110110010000000111…
…111101001100101110001
3120021102222202220211120012
4332302000333221211301
51031141202200144012
613101544532424305
7623461441161161
oct76620077514561
916242882824505
104314311334257
111413764302141
12598186178095
13253ab78a1c62
1410cb5703c5a1
1577359c99622
hex3ec80fe9971

4314311334257 has 2 divisors, whose sum is σ = 4314311334258. Its totient is φ = 4314311334256.

The previous prime is 4314311334197. The next prime is 4314311334259. The reversal of 4314311334257 is 7524331134134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2694798029056 + 1619513305201 = 1641584^2 + 1272601^2 .

It is a cyclic number.

It is not a de Polignac number, because 4314311334257 - 238 = 4039433427313 is a prime.

It is a super-2 number, since 2×43143113342572 (a number of 26 digits) contains 22 as substring.

Together with 4314311334259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4314311334259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157155667128 + 2157155667129.

It is an arithmetic number, because the mean of its divisors is an integer number (2157155667129).

Almost surely, 24314311334257 is an apocalyptic number.

It is an amenable number.

4314311334257 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314311334257 is an equidigital number, since it uses as much as digits as its factorization.

4314311334257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 362880, while the sum is 41.

The spelling of 4314311334257 in words is "four trillion, three hundred fourteen billion, three hundred eleven million, three hundred thirty-four thousand, two hundred fifty-seven".