43143241213 has 4 divisors (see below), whose sum is σ = 44146572448. Its totient is φ = 42139909980.

The previous prime is 43143241199. The next prime is 43143241249. The reversal of 43143241213 is 31214234134.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31214234134 = 2 ⋅15607117067.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43143241213 is a prime.

It is a super-3 number, since 3×43143241213³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43143241513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501665553 + ... + 501665638.

It is an arithmetic number, because the mean of its divisors is an integer number (11036643112).

Almost surely, 2^43143241213 is an apocalyptic number.

43143241213 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

43143241213 is a deficient number, since it is larger than the sum of its proper divisors (1003331235).

43143241213 is a wasteful number, since it uses less digits than its factorization.

43143241213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1003331234.

The product of its digits is 6912, while the sum is 28.

Adding to 43143241213 its reverse (31214234134), we get a palindrome (74357475347).

The spelling of 43143241213 in words is "forty-three billion, one hundred forty-three million, two hundred forty-one thousand, two hundred thirteen".