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43143300263101 is a prime number
BaseRepresentation
bin10011100111101000101010…
…00101100010110010111101
312122202110101202220220101111
421303310111011202302331
521123324434331404401
6231431431501442021
712042000125326333
oct1163642505426275
9178673352826344
1043143300263101
1112823a75289455
124a09563b70311
131b0c51b63164c
14a9220b047b53
154ec3c9c87e51
hex273d15162cbd

43143300263101 has 2 divisors, whose sum is σ = 43143300263102. Its totient is φ = 43143300263100.

The previous prime is 43143300263087. The next prime is 43143300263111. The reversal of 43143300263101 is 10136200334134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36118309042201 + 7024991220900 = 6009851^2 + 2650470^2 .

It is a cyclic number.

It is not a de Polignac number, because 43143300263101 - 229 = 43142763392189 is a prime.

It is a super-2 number, since 2×431433002631012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43143300263111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571650131550 + 21571650131551.

It is an arithmetic number, because the mean of its divisors is an integer number (21571650131551).

Almost surely, 243143300263101 is an apocalyptic number.

It is an amenable number.

43143300263101 is a deficient number, since it is larger than the sum of its proper divisors (1).

43143300263101 is an equidigital number, since it uses as much as digits as its factorization.

43143300263101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 43143300263101 its reverse (10136200334134), we get a palindrome (53279500597235).

The spelling of 43143300263101 in words is "forty-three trillion, one hundred forty-three billion, three hundred million, two hundred sixty-three thousand, one hundred one".