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43143314012230 = 2519322354048711
BaseRepresentation
bin10011100111101000101011…
…11001111111100001000110
312122202110102201210102122111
421303310111321333201012
521123330001341342410
6231431433112251234
712042000353232265
oct1163642571774106
9178673381712574
1043143314012230
1112823a8201a373
124a095686a0b1a
131b0c521436823
14a9220cbc65dc
154ec3cb0a1b8a
hex273d15e7f846

43143314012230 has 16 divisors (see below), whose sum is σ = 78060338102304. Its totient is φ = 17167909409280.

The previous prime is 43143314012221. The next prime is 43143314012237. The reversal of 43143314012230 is 3221041334134.

It is a super-2 number, since 2×431433140122302 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43143314012192 and 43143314012201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43143314012237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11177022426 + ... + 11177026285.

It is an arithmetic number, because the mean of its divisors is an integer number (4878771131394).

Almost surely, 243143314012230 is an apocalyptic number.

43143314012230 is a deficient number, since it is larger than the sum of its proper divisors (34917024090074).

43143314012230 is a wasteful number, since it uses less digits than its factorization.

43143314012230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22354048911.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 43143314012230 its reverse (3221041334134), we get a palindrome (46364355346364).

The spelling of 43143314012230 in words is "forty-three trillion, one hundred forty-three billion, three hundred fourteen million, twelve thousand, two hundred thirty".

Divisors: 1 2 5 10 193 386 965 1930 22354048711 44708097422 111770243555 223540487110 4314331401223 8628662802446 21571657006115 43143314012230