Base | Representation |
---|---|
bin | 10011100111101010011001… |
… | …01111100010110100100011 |
3 | 12122202112210211221200020012 |
4 | 21303311030233202310203 |
5 | 21123333342402121011 |
6 | 231432104255235135 |
7 | 12042032224202126 |
oct | 1163651457426443 |
9 | 178675724850205 |
10 | 43144234020131 |
11 | 12824404377982 |
12 | 4a09784818aab |
13 | 1b0c639c170ba |
14 | a922990703bd |
15 | 4ec431c31a8b |
hex | 273d4cbe2d23 |
43144234020131 has 2 divisors, whose sum is σ = 43144234020132. Its totient is φ = 43144234020130.
The previous prime is 43144234020071. The next prime is 43144234020137. The reversal of 43144234020131 is 13102043244134.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43144234020131 is a prime.
It is a super-2 number, since 2×431442340201312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43144234020137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21572117010065 + 21572117010066.
It is an arithmetic number, because the mean of its divisors is an integer number (21572117010066).
Almost surely, 243144234020131 is an apocalyptic number.
43144234020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
43144234020131 is an equidigital number, since it uses as much as digits as its factorization.
43144234020131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 43144234020131 its reverse (13102043244134), we get a palindrome (56246277264265).
The spelling of 43144234020131 in words is "forty-three trillion, one hundred forty-four billion, two hundred thirty-four million, twenty thousand, one hundred thirty-one".
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