Base | Representation |
---|---|
bin | 10011100111111000111010… |
… | …10011100100101111001111 |
3 | 12122210021221000212121202012 |
4 | 21303330131103210233033 |
5 | 21124000323142442031 |
6 | 231435433521251435 |
7 | 12042426324551600 |
oct | 1163743523445717 |
9 | 178707830777665 |
10 | 43152028093391 |
11 | 12827743984538 |
12 | 4a0b19aa93b7b |
13 | 1b102ac8a9379 |
14 | a927d8251da7 |
15 | 4ec73b101b2b |
hex | 273f1d4e4bcf |
43152028093391 has 24 divisors (see below), whose sum is σ = 50342528206224. Its totient is φ = 36880423641600.
The previous prime is 43152028093381. The next prime is 43152028093459. The reversal of 43152028093391 is 19339082025134.
It is not a de Polignac number, because 43152028093391 - 222 = 43152023899087 is a prime.
It is a super-2 number, since 2×431520280933912 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43152028093301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 323404496 + ... + 323537898.
It is an arithmetic number, because the mean of its divisors is an integer number (2097605341926).
Almost surely, 243152028093391 is an apocalyptic number.
43152028093391 is a deficient number, since it is larger than the sum of its proper divisors (7190500112833).
43152028093391 is a wasteful number, since it uses less digits than its factorization.
43152028093391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152471 (or 152464 counting only the distinct ones).
The product of its (nonzero) digits is 1399680, while the sum is 50.
The spelling of 43152028093391 in words is "forty-three trillion, one hundred fifty-two billion, twenty-eight million, ninety-three thousand, three hundred ninety-one".
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