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43155135113 is a prime number
BaseRepresentation
bin101000001100001111…
…110001101010001001
311010101120000000012112
4220030033301222021
51201340203310423
631454124152105
73055265411306
oct501417615211
9133346000175
1043155135113
1117335a48822
128444698635
1340b994310c
1421356380ad
1511c89c1a78
hexa0c3f1a89

43155135113 has 2 divisors, whose sum is σ = 43155135114. Its totient is φ = 43155135112.

The previous prime is 43155135097. The next prime is 43155135143. The reversal of 43155135113 is 31153155134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28565394169 + 14589740944 = 169013^2 + 120788^2 .

It is a cyclic number.

It is not a de Polignac number, because 43155135113 - 24 = 43155135097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 43155135113.

It is not a weakly prime, because it can be changed into another prime (43155135143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21577567556 + 21577567557.

It is an arithmetic number, because the mean of its divisors is an integer number (21577567557).

Almost surely, 243155135113 is an apocalyptic number.

It is an amenable number.

43155135113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43155135113 is an equidigital number, since it uses as much as digits as its factorization.

43155135113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13500, while the sum is 32.

It can be divided in two parts, 431551 and 35113, that added together give a palindrome (466664).

The spelling of 43155135113 in words is "forty-three billion, one hundred fifty-five million, one hundred thirty-five thousand, one hundred thirteen".