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432000134017 is a prime number
BaseRepresentation
bin1100100100101010011…
…01101110101110000001
31112022001211110121102121
412102111031232232001
524034214013242032
6530242542044241
743132236360244
oct6222515565601
91468054417377
10432000134017
111572348a4751
126b883b79681
13319781c679a
1416ca20dd25b
15b385e0ea97
hex649536eb81

432000134017 has 2 divisors, whose sum is σ = 432000134018. Its totient is φ = 432000134016.

The previous prime is 432000134009. The next prime is 432000134023. The reversal of 432000134017 is 710431000234.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 280056873616 + 151943260401 = 529204^2 + 389799^2 .

It is a cyclic number.

It is not a de Polignac number, because 432000134017 - 23 = 432000134009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 432000133982 and 432000134000.

It is not a weakly prime, because it can be changed into another prime (432000164017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216000067008 + 216000067009.

It is an arithmetic number, because the mean of its divisors is an integer number (216000067009).

Almost surely, 2432000134017 is an apocalyptic number.

It is an amenable number.

432000134017 is a deficient number, since it is larger than the sum of its proper divisors (1).

432000134017 is an equidigital number, since it uses as much as digits as its factorization.

432000134017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 25.

The spelling of 432000134017 in words is "four hundred thirty-two billion, one hundred thirty-four thousand, seventeen".