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4320131430053 is a prime number
BaseRepresentation
bin111110110111011011111…
…001100011011010100101
3120022000000101110100001202
4332313123321203122211
51031240112121230203
613104350241332245
7624055612160405
oct76673371433245
916260011410052
104320131430053
11141618062626a
1259932b337085
132545045cb61a
1410d149dba805
157759abe7388
hex3eddbe636a5

4320131430053 has 2 divisors, whose sum is σ = 4320131430054. Its totient is φ = 4320131430052.

The previous prime is 4320131430023. The next prime is 4320131430127. The reversal of 4320131430053 is 3500341310234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3647859343969 + 672272086084 = 1909937^2 + 819922^2 .

It is a cyclic number.

It is not a de Polignac number, because 4320131430053 - 230 = 4319057688229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4320131429998 and 4320131430025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4320131430023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2160065715026 + 2160065715027.

It is an arithmetic number, because the mean of its divisors is an integer number (2160065715027).

Almost surely, 24320131430053 is an apocalyptic number.

It is an amenable number.

4320131430053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4320131430053 is an equidigital number, since it uses as much as digits as its factorization.

4320131430053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 4320131430053 its reverse (3500341310234), we get a palindrome (7820472740287).

The spelling of 4320131430053 in words is "four trillion, three hundred twenty billion, one hundred thirty-one million, four hundred thirty thousand, fifty-three".